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135044254019 is a prime number
BaseRepresentation
bin111110111000101000…
…0111100100101000011
3110220120110120220021202
41331301100330211003
54203032312112034
6142012151011415
712520344135203
oct1756120744503
9426513526252
10135044254019
11522a9a62904
122220a069b6b
13c971c5931c
1467713aa403
1537a5b0c47e
hex1f7143c943

135044254019 has 2 divisors, whose sum is σ = 135044254020. Its totient is φ = 135044254018.

The previous prime is 135044253991. The next prime is 135044254069. The reversal of 135044254019 is 910452440531.

It is a weak prime.

It is an emirp because it is prime and its reverse (910452440531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135044254019 is a prime.

It is a super-2 number, since 2×1350442540192 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135044254069) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67522127009 + 67522127010.

It is an arithmetic number, because the mean of its divisors is an integer number (67522127010).

Almost surely, 2135044254019 is an apocalyptic number.

135044254019 is a deficient number, since it is larger than the sum of its proper divisors (1).

135044254019 is an equidigital number, since it uses as much as digits as its factorization.

135044254019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 38.

The spelling of 135044254019 in words is "one hundred thirty-five billion, forty-four million, two hundred fifty-four thousand, nineteen".