Base | Representation |
---|---|
bin | 111110111000101000… |
… | …0111100100101010011 |
3 | 110220120110120220022100 |
4 | 1331301100330211103 |
5 | 4203032312112120 |
6 | 142012151011443 |
7 | 12520344135225 |
oct | 1756120744523 |
9 | 426513526270 |
10 | 135044254035 |
11 | 522a9a62919 |
12 | 2220a069b83 |
13 | c971c59332 |
14 | 67713aa415 |
15 | 37a5b0c490 |
hex | 1f7143c953 |
135044254035 has 24 divisors (see below), whose sum is σ = 242148319920. Its totient is φ = 69540028992.
The previous prime is 135044254019. The next prime is 135044254069. The reversal of 135044254035 is 530452440531.
135044254035 is a `hidden beast` number, since 135 + 0 + 442 + 54 + 0 + 35 = 666.
It is not a de Polignac number, because 135044254035 - 24 = 135044254019 is a prime.
It is a super-2 number, since 2×1350442540352 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 51739789 + ... + 51742398.
It is an arithmetic number, because the mean of its divisors is an integer number (10089513330).
Almost surely, 2135044254035 is an apocalyptic number.
135044254035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
135044254035 is a deficient number, since it is larger than the sum of its proper divisors (107104065885).
135044254035 is a wasteful number, since it uses less digits than its factorization.
135044254035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103482227 (or 103482224 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 36.
Adding to 135044254035 its reverse (530452440531), we get a palindrome (665496694566).
The spelling of 135044254035 in words is "one hundred thirty-five billion, forty-four million, two hundred fifty-four thousand, thirty-five".
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