Base | Representation |
---|---|
bin | 1100010010000100001011… |
… | …1100111001101011110111 |
3 | 1202211000110212002021022112 |
4 | 3010201002330321223313 |
5 | 3232224204103033144 |
6 | 44415514251521235 |
7 | 2562445052522555 |
oct | 304410274715367 |
9 | 52730425067275 |
10 | 13504500439799 |
11 | 4337254489226 |
12 | 1621319a5921b |
13 | 76c613304c05 |
14 | 34989ac2abd5 |
15 | 18643a44399e |
hex | c4842f39af7 |
13504500439799 has 2 divisors, whose sum is σ = 13504500439800. Its totient is φ = 13504500439798.
The previous prime is 13504500439693. The next prime is 13504500439861. The reversal of 13504500439799 is 99793400540531.
It is a strong prime.
It is an emirp because it is prime and its reverse (99793400540531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13504500439799 - 28 = 13504500439543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13504500439099) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6752250219899 + 6752250219900.
It is an arithmetic number, because the mean of its divisors is an integer number (6752250219900).
Almost surely, 213504500439799 is an apocalyptic number.
13504500439799 is a deficient number, since it is larger than the sum of its proper divisors (1).
13504500439799 is an equidigital number, since it uses as much as digits as its factorization.
13504500439799 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18370800, while the sum is 59.
The spelling of 13504500439799 in words is "thirteen trillion, five hundred four billion, five hundred million, four hundred thirty-nine thousand, seven hundred ninety-nine".
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