Search a number
-
+
1350454046503 is a prime number
BaseRepresentation
bin10011101001101101010…
…101010110111100100111
311210002202110112120120011
4103221231111112330213
5134111212213442003
62512220124551051
7166365336666022
oct23515525267447
94702673476504
101350454046503
114807a7115091
121998883b2487
139a468c4c923
144951030c1b9
15251dd5a746d
hex13a6d556f27

1350454046503 has 2 divisors, whose sum is σ = 1350454046504. Its totient is φ = 1350454046502.

The previous prime is 1350454046441. The next prime is 1350454046519. The reversal of 1350454046503 is 3056404540531.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1350454046503 is a prime.

It is a super-2 number, since 2×13504540465032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1350454046533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675227023251 + 675227023252.

It is an arithmetic number, because the mean of its divisors is an integer number (675227023252).

Almost surely, 21350454046503 is an apocalyptic number.

1350454046503 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350454046503 is an equidigital number, since it uses as much as digits as its factorization.

1350454046503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 40.

The spelling of 1350454046503 in words is "one trillion, three hundred fifty billion, four hundred fifty-four million, forty-six thousand, five hundred three".