Base | Representation |
---|---|
bin | 10011101001101111111… |
… | …000100010011100001011 |
3 | 11210002212110000211221202 |
4 | 103221233320202130023 |
5 | 134111304141314201 |
6 | 2512224253454415 |
7 | 166366366410005 |
oct | 23515770423413 |
9 | 4702773024852 |
10 | 1350496823051 |
11 | 480819281802 |
12 | 19989a7a140b |
13 | 9a474a791ac |
14 | 49515c85375 |
15 | 251e2206c6b |
hex | 13a6fe2270b |
1350496823051 has 2 divisors, whose sum is σ = 1350496823052. Its totient is φ = 1350496823050.
The previous prime is 1350496823009. The next prime is 1350496823111. The reversal of 1350496823051 is 1503286940531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1350496823051 - 238 = 1075618916107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1350496822987 and 1350496823005.
It is not a weakly prime, because it can be changed into another prime (1350496853051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675248411525 + 675248411526.
It is an arithmetic number, because the mean of its divisors is an integer number (675248411526).
Almost surely, 21350496823051 is an apocalyptic number.
1350496823051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350496823051 is an equidigital number, since it uses as much as digits as its factorization.
1350496823051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 777600, while the sum is 47.
The spelling of 1350496823051 in words is "one trillion, three hundred fifty billion, four hundred ninety-six million, eight hundred twenty-three thousand, fifty-one".
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