Base | Representation |
---|---|
bin | 111110111000111001… |
… | …0101111111001000011 |
3 | 110220121002021002012021 |
4 | 1331301302233321003 |
5 | 4203042044134242 |
6 | 142013104542311 |
7 | 12520512351622 |
oct | 1756162577103 |
9 | 426532232167 |
10 | 135053114947 |
11 | 52303a65193 |
12 | 22211021997 |
13 | c973a3c58a |
14 | 67726356b9 |
15 | 37a67acb67 |
hex | 1f71cafe43 |
135053114947 has 2 divisors, whose sum is σ = 135053114948. Its totient is φ = 135053114946.
The previous prime is 135053114941. The next prime is 135053114981. The reversal of 135053114947 is 749411350531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135053114947 - 227 = 134918897219 is a prime.
It is not a weakly prime, because it can be changed into another prime (135053114941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67526557473 + 67526557474.
It is an arithmetic number, because the mean of its divisors is an integer number (67526557474).
Almost surely, 2135053114947 is an apocalyptic number.
135053114947 is a deficient number, since it is larger than the sum of its proper divisors (1).
135053114947 is an equidigital number, since it uses as much as digits as its factorization.
135053114947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 226800, while the sum is 43.
It can be divided in two parts, 135053 and 114947, that added together give a square (250000 = 5002).
The spelling of 135053114947 in words is "one hundred thirty-five billion, fifty-three million, one hundred fourteen thousand, nine hundred forty-seven".
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