Base | Representation |
---|---|
bin | 111110111000111001… |
… | …0101111111001100101 |
3 | 110220121002021002020112 |
4 | 1331301302233321211 |
5 | 4203042044134411 |
6 | 142013104542405 |
7 | 12520512352001 |
oct | 1756162577145 |
9 | 426532232215 |
10 | 135053114981 |
11 | 52303a65214 |
12 | 22211021a05 |
13 | c973a3c5b5 |
14 | 6772635701 |
15 | 37a67acb8b |
hex | 1f71cafe65 |
135053114981 has 2 divisors, whose sum is σ = 135053114982. Its totient is φ = 135053114980.
The previous prime is 135053114947. The next prime is 135053115017. The reversal of 135053114981 is 189411350531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84713013025 + 50340101956 = 291055^2 + 224366^2 .
It is a cyclic number.
It is not a de Polignac number, because 135053114981 - 214 = 135053098597 is a prime.
It is a super-2 number, since 2×1350531149812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135053114941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67526557490 + 67526557491.
It is an arithmetic number, because the mean of its divisors is an integer number (67526557491).
Almost surely, 2135053114981 is an apocalyptic number.
It is an amenable number.
135053114981 is a deficient number, since it is larger than the sum of its proper divisors (1).
135053114981 is an equidigital number, since it uses as much as digits as its factorization.
135053114981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 41.
The spelling of 135053114981 in words is "one hundred thirty-five billion, fifty-three million, one hundred fourteen thousand, nine hundred eighty-one".
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