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135053114981 is a prime number
BaseRepresentation
bin111110111000111001…
…0101111111001100101
3110220121002021002020112
41331301302233321211
54203042044134411
6142013104542405
712520512352001
oct1756162577145
9426532232215
10135053114981
1152303a65214
1222211021a05
13c973a3c5b5
146772635701
1537a67acb8b
hex1f71cafe65

135053114981 has 2 divisors, whose sum is σ = 135053114982. Its totient is φ = 135053114980.

The previous prime is 135053114947. The next prime is 135053115017. The reversal of 135053114981 is 189411350531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84713013025 + 50340101956 = 291055^2 + 224366^2 .

It is a cyclic number.

It is not a de Polignac number, because 135053114981 - 214 = 135053098597 is a prime.

It is a super-2 number, since 2×1350531149812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135053114941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67526557490 + 67526557491.

It is an arithmetic number, because the mean of its divisors is an integer number (67526557491).

Almost surely, 2135053114981 is an apocalyptic number.

It is an amenable number.

135053114981 is a deficient number, since it is larger than the sum of its proper divisors (1).

135053114981 is an equidigital number, since it uses as much as digits as its factorization.

135053114981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 41.

The spelling of 135053114981 in words is "one hundred thirty-five billion, fifty-three million, one hundred fourteen thousand, nine hundred eighty-one".