Base | Representation |
---|---|
bin | 1100010010000111111100… |
… | …1111101100111010101101 |
3 | 1202211010002100111220200111 |
4 | 3010201333033230322231 |
5 | 3232233242033014242 |
6 | 44420202505100021 |
7 | 2562512114615266 |
oct | 304417717547255 |
9 | 52733070456614 |
10 | 13505512001197 |
11 | 4337723489287 |
12 | 1621560787611 |
13 | 76c744a5c558 |
14 | 34995530796d |
15 | 18649915a817 |
hex | c487f3ecead |
13505512001197 has 2 divisors, whose sum is σ = 13505512001198. Its totient is φ = 13505512001196.
The previous prime is 13505512001183. The next prime is 13505512001329. The reversal of 13505512001197 is 79110021550531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11903955944521 + 1601556056676 = 3450211^2 + 1265526^2 .
It is a cyclic number.
It is not a de Polignac number, because 13505512001197 - 211 = 13505511999149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13505812001197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6752756000598 + 6752756000599.
It is an arithmetic number, because the mean of its divisors is an integer number (6752756000599).
Almost surely, 213505512001197 is an apocalyptic number.
It is an amenable number.
13505512001197 is a deficient number, since it is larger than the sum of its proper divisors (1).
13505512001197 is an equidigital number, since it uses as much as digits as its factorization.
13505512001197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47250, while the sum is 40.
The spelling of 13505512001197 in words is "thirteen trillion, five hundred five billion, five hundred twelve million, one thousand, one hundred ninety-seven".
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