Base | Representation |
---|---|
bin | 10011101001110011100… |
… | …000100110010111011111 |
3 | 11210010000200111111211001 |
4 | 103221303200212113133 |
5 | 134111420230002133 |
6 | 2512234305411131 |
7 | 166401035445064 |
oct | 23516340462737 |
9 | 4703020444731 |
10 | 1350557656543 |
11 | 48084a651917 |
12 | 1998b7039aa7 |
13 | 9a484558644 |
14 | 4951dd9cc6b |
15 | 251e772187d |
hex | 13a738265df |
1350557656543 has 2 divisors, whose sum is σ = 1350557656544. Its totient is φ = 1350557656542.
The previous prime is 1350557656529. The next prime is 1350557656549. The reversal of 1350557656543 is 3456567550531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1350557656543 - 213 = 1350557648351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1350557656549) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675278828271 + 675278828272.
It is an arithmetic number, because the mean of its divisors is an integer number (675278828272).
Almost surely, 21350557656543 is an apocalyptic number.
1350557656543 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350557656543 is an equidigital number, since it uses as much as digits as its factorization.
1350557656543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28350000, while the sum is 55.
The spelling of 1350557656543 in words is "one trillion, three hundred fifty billion, five hundred fifty-seven million, six hundred fifty-six thousand, five hundred forty-three".
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