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135064471 is a prime number
BaseRepresentation
bin10000000110011…
…10101110010111
3100102010222121211
420003032232113
5234034030341
621222522251
73230012653
oct1003165627
9312128554
10135064471
116a270a33
1239296387
1321c9ca09
1413d1ba63
15bcce181
hex80ceb97

135064471 has 2 divisors, whose sum is σ = 135064472. Its totient is φ = 135064470.

The previous prime is 135064453. The next prime is 135064499. The reversal of 135064471 is 174460531.

135064471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 135064471 - 211 = 135062423 is a prime.

It is a super-3 number, since 3×1350644713 (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135064411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67532235 + 67532236.

It is an arithmetic number, because the mean of its divisors is an integer number (67532236).

Almost surely, 2135064471 is an apocalyptic number.

135064471 is a deficient number, since it is larger than the sum of its proper divisors (1).

135064471 is an equidigital number, since it uses as much as digits as its factorization.

135064471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

The square root of 135064471 is about 11621.7240975683. The cubic root of 135064471 is about 513.0744331248.

The spelling of 135064471 in words is "one hundred thirty-five million, sixty-four thousand, four hundred seventy-one".