Base | Representation |
---|---|
bin | 111110111001001111… |
… | …0010000010110001101 |
3 | 110220121212201112002111 |
4 | 1331302132100112031 |
5 | 4203103004120302 |
6 | 142014153224021 |
7 | 12521011323004 |
oct | 1756236202615 |
9 | 426555645074 |
10 | 135064520077 |
11 | 5230a445013 |
12 | 22214a02011 |
13 | c976203886 |
14 | 6773d63c3b |
15 | 37a77b20d7 |
hex | 1f7279058d |
135064520077 has 2 divisors, whose sum is σ = 135064520078. Its totient is φ = 135064520076.
The previous prime is 135064519991. The next prime is 135064520081. The reversal of 135064520077 is 770025460531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 93175120516 + 41889399561 = 305246^2 + 204669^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135064520077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135064520777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67532260038 + 67532260039.
It is an arithmetic number, because the mean of its divisors is an integer number (67532260039).
Almost surely, 2135064520077 is an apocalyptic number.
It is an amenable number.
135064520077 is a deficient number, since it is larger than the sum of its proper divisors (1).
135064520077 is an equidigital number, since it uses as much as digits as its factorization.
135064520077 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 176400, while the sum is 40.
The spelling of 135064520077 in words is "one hundred thirty-five billion, sixty-four million, five hundred twenty thousand, seventy-seven".
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