Base | Representation |
---|---|
bin | 10011101001111011110… |
… | …011111010000100000001 |
3 | 11210010101101120121212122 |
4 | 103221323303322010001 |
5 | 134112211403420211 |
6 | 2512300202534025 |
7 | 166404346343522 |
oct | 23517363720401 |
9 | 4703341517778 |
10 | 1350696935681 |
11 | 480911231345 |
12 | 199935807315 |
13 | 9a4a7372832 |
14 | 49534696849 |
15 | 25204a846db |
hex | 13a7bcfa101 |
1350696935681 has 2 divisors, whose sum is σ = 1350696935682. Its totient is φ = 1350696935680.
The previous prime is 1350696935671. The next prime is 1350696935711. The reversal of 1350696935681 is 1865396960531.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1153725181456 + 196971754225 = 1074116^2 + 443815^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1350696935681 is a prime.
It is a super-2 number, since 2×13506969356812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1350696935671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675348467840 + 675348467841.
It is an arithmetic number, because the mean of its divisors is an integer number (675348467841).
Almost surely, 21350696935681 is an apocalyptic number.
It is an amenable number.
1350696935681 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350696935681 is an equidigital number, since it uses as much as digits as its factorization.
1350696935681 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31492800, while the sum is 62.
The spelling of 1350696935681 in words is "one trillion, three hundred fifty billion, six hundred ninety-six million, nine hundred thirty-five thousand, six hundred eighty-one".
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