Base | Representation |
---|---|
bin | 10011101010000101000… |
… | …001011011100000010001 |
3 | 11210010210011101001121122 |
4 | 103222011001123200101 |
5 | 134113020434203343 |
6 | 2512323403132025 |
7 | 166411234042043 |
oct | 23520501334021 |
9 | 4703704331548 |
10 | 1350851475473 |
11 | 480990494385 |
12 | 199979514015 |
13 | 9a5003a0bb6 |
14 | 4954b003a93 |
15 | 2521340e068 |
hex | 13a8505b811 |
1350851475473 has 2 divisors, whose sum is σ = 1350851475474. Its totient is φ = 1350851475472.
The previous prime is 1350851475419. The next prime is 1350851475503. The reversal of 1350851475473 is 3745741580531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1068883041424 + 281968434049 = 1033868^2 + 531007^2 .
It is a cyclic number.
It is not a de Polignac number, because 1350851475473 - 26 = 1350851475409 is a prime.
It is a super-2 number, since 2×13508514754732 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1350851475773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675425737736 + 675425737737.
It is an arithmetic number, because the mean of its divisors is an integer number (675425737737).
Almost surely, 21350851475473 is an apocalyptic number.
It is an amenable number.
1350851475473 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350851475473 is an equidigital number, since it uses as much as digits as its factorization.
1350851475473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7056000, while the sum is 53.
The spelling of 1350851475473 in words is "one trillion, three hundred fifty billion, eight hundred fifty-one million, four hundred seventy-five thousand, four hundred seventy-three".
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