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135089127949 is a prime number
BaseRepresentation
bin111110111001111110…
…0001000001000001101
3110220200121000201202011
41331303330020020031
54203130304043244
6142020432501221
712521430433036
oct1756374101015
9426617021664
10135089127949
11523223222a6
12222210aa811
13c97b33b449
14677732ba8d
1537a9a23434
hex1f73f0820d

135089127949 has 2 divisors, whose sum is σ = 135089127950. Its totient is φ = 135089127948.

The previous prime is 135089127937. The next prime is 135089127959. The reversal of 135089127949 is 949721980531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131598445225 + 3490682724 = 362765^2 + 59082^2 .

It is an emirp because it is prime and its reverse (949721980531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135089127949 - 215 = 135089095181 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135089127893 and 135089127902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135089127959) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67544563974 + 67544563975.

It is an arithmetic number, because the mean of its divisors is an integer number (67544563975).

Almost surely, 2135089127949 is an apocalyptic number.

It is an amenable number.

135089127949 is a deficient number, since it is larger than the sum of its proper divisors (1).

135089127949 is an equidigital number, since it uses as much as digits as its factorization.

135089127949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 58.

The spelling of 135089127949 in words is "one hundred thirty-five billion, eighty-nine million, one hundred twenty-seven thousand, nine hundred forty-nine".