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1350962426893 is a prime number
BaseRepresentation
bin10011101010001011101…
…000101011010000001101
311210011001220010222100111
4103222023220223100031
5134113232340130033
62512342405200021
7166414052105422
oct23521350532015
94704056128314
101350962426893
11480a38085872
121999aa700011
139a51a37a321
144955ba45d49
152521d0287cd
hex13a8ba2b40d

1350962426893 has 2 divisors, whose sum is σ = 1350962426894. Its totient is φ = 1350962426892.

The previous prime is 1350962426861. The next prime is 1350962426911. The reversal of 1350962426893 is 3986242690531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 834378114249 + 516584312644 = 913443^2 + 718738^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350962426893 - 25 = 1350962426861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1350962426843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675481213446 + 675481213447.

It is an arithmetic number, because the mean of its divisors is an integer number (675481213447).

Almost surely, 21350962426893 is an apocalyptic number.

It is an amenable number.

1350962426893 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350962426893 is an equidigital number, since it uses as much as digits as its factorization.

1350962426893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16796160, while the sum is 58.

The spelling of 1350962426893 in words is "one trillion, three hundred fifty billion, nine hundred sixty-two million, four hundred twenty-six thousand, eight hundred ninety-three".