Base | Representation |
---|---|
bin | 111110111010010010… |
… | …1111110111011110111 |
3 | 110220201100200012001010 |
4 | 1331310211332323313 |
5 | 4203141111202333 |
6 | 142021504003303 |
7 | 12521622622365 |
oct | 1756445767367 |
9 | 426640605033 |
10 | 135100100343 |
11 | 52328536a9a |
12 | 22224900533 |
13 | c9806b07a0 |
14 | 6778986635 |
15 | 37aa98e563 |
hex | 1f7497eef7 |
135100100343 has 64 divisors (see below), whose sum is σ = 211396792320. Its totient is φ = 76001587200.
The previous prime is 135100100327. The next prime is 135100100363. The reversal of 135100100343 is 343001001531.
It is not a de Polignac number, because 135100100343 - 24 = 135100100327 is a prime.
It is a super-2 number, since 2×1351001003432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135100100363) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8100433 + ... + 8117093.
It is an arithmetic number, because the mean of its divisors is an integer number (3303074880).
Almost surely, 2135100100343 is an apocalyptic number.
135100100343 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
135100100343 is a deficient number, since it is larger than the sum of its proper divisors (76296691977).
135100100343 is a wasteful number, since it uses less digits than its factorization.
135100100343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17080.
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 135100100343 its reverse (343001001531), we get a palindrome (478101101874).
The spelling of 135100100343 in words is "one hundred thirty-five billion, one hundred million, one hundred thousand, three hundred forty-three".
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