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1351041755681 is a prime number
BaseRepresentation
bin10011101010010000010…
…111010010101000100001
311210011021102102021222202
4103222100113102220201
5134113413142140211
62512354321342545
7166416034304612
oct23522027225041
94704242367882
101351041755681
11480a78938752
12199a11197a55
139a530934037
14495683b5c09
1525224e9853b
hex13a905d2a21

1351041755681 has 2 divisors, whose sum is σ = 1351041755682. Its totient is φ = 1351041755680.

The previous prime is 1351041755671. The next prime is 1351041755699. The reversal of 1351041755681 is 1865571401531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1113624320656 + 237417435025 = 1055284^2 + 487255^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1351041755681 is a prime.

It is a super-2 number, since 2×13510417556812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1351041755611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675520877840 + 675520877841.

It is an arithmetic number, because the mean of its divisors is an integer number (675520877841).

Almost surely, 21351041755681 is an apocalyptic number.

It is an amenable number.

1351041755681 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351041755681 is an equidigital number, since it uses as much as digits as its factorization.

1351041755681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504000, while the sum is 47.

The spelling of 1351041755681 in words is "one trillion, three hundred fifty-one billion, forty-one million, seven hundred fifty-five thousand, six hundred eighty-one".