Base | Representation |
---|---|
bin | 10011101010010100000… |
… | …101100000111101001001 |
3 | 11210011102202221000211022 |
4 | 103222110011200331021 |
5 | 134114030134021432 |
6 | 2512404432042225 |
7 | 166420423151516 |
oct | 23522405407511 |
9 | 4704382830738 |
10 | 1351104204617 |
11 | 481000111542 |
12 | 199a2a093375 |
13 | 9a54085a87b |
14 | 495727d030d |
15 | 2522a6d1b12 |
hex | 13a94160f49 |
1351104204617 has 2 divisors, whose sum is σ = 1351104204618. Its totient is φ = 1351104204616.
The previous prime is 1351104204551. The next prime is 1351104204641. The reversal of 1351104204617 is 7164024011531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 881215890361 + 469888314256 = 938731^2 + 685484^2 .
It is an emirp because it is prime and its reverse (7164024011531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1351104204617 - 210 = 1351104203593 is a prime.
It is not a weakly prime, because it can be changed into another prime (1351104204217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675552102308 + 675552102309.
It is an arithmetic number, because the mean of its divisors is an integer number (675552102309).
Almost surely, 21351104204617 is an apocalyptic number.
It is an amenable number.
1351104204617 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351104204617 is an equidigital number, since it uses as much as digits as its factorization.
1351104204617 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 1351104204617 in words is "one trillion, three hundred fifty-one billion, one hundred four million, two hundred four thousand, six hundred seventeen".
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