Base | Representation |
---|---|
bin | 10011101010010100000… |
… | …101100000111100000111 |
3 | 11210011102202221000201212 |
4 | 103222110011200330013 |
5 | 134114030134021201 |
6 | 2512404432042035 |
7 | 166420423151363 |
oct | 23522405407407 |
9 | 4704382830655 |
10 | 1351104204551 |
11 | 481000111492 |
12 | 199a2a09331b |
13 | 9a54085a82a |
14 | 495727d02a3 |
15 | 2522a6d1abb |
hex | 13a94160f07 |
1351104204551 has 2 divisors, whose sum is σ = 1351104204552. Its totient is φ = 1351104204550.
The previous prime is 1351104204539. The next prime is 1351104204617. The reversal of 1351104204551 is 1554024011531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1351104204551 - 218 = 1351103942407 is a prime.
It is a super-2 number, since 2×13511042045512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351104204251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675552102275 + 675552102276.
It is an arithmetic number, because the mean of its divisors is an integer number (675552102276).
Almost surely, 21351104204551 is an apocalyptic number.
1351104204551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351104204551 is an equidigital number, since it uses as much as digits as its factorization.
1351104204551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 1351104204551 in words is "one trillion, three hundred fifty-one billion, one hundred four million, two hundred four thousand, five hundred fifty-one".
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