Base | Representation |
---|---|
bin | 10011101010010100000… |
… | …101100110001101011101 |
3 | 11210011102202222010100111 |
4 | 103222110011212031131 |
5 | 134114030140214031 |
6 | 2512404432330021 |
7 | 166420423301335 |
oct | 23522405461535 |
9 | 4704382863314 |
10 | 1351104226141 |
11 | 48100012672a |
12 | 199a2a0a3911 |
13 | 9a5408675c7 |
14 | 495727d80c5 |
15 | 2522a6d81b1 |
hex | 13a9416635d |
1351104226141 has 2 divisors, whose sum is σ = 1351104226142. Its totient is φ = 1351104226140.
The previous prime is 1351104226093. The next prime is 1351104226159. The reversal of 1351104226141 is 1416224011531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1120324870116 + 230779356025 = 1058454^2 + 480395^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351104226141 - 227 = 1350970008413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351104226181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675552113070 + 675552113071.
It is an arithmetic number, because the mean of its divisors is an integer number (675552113071).
Almost surely, 21351104226141 is an apocalyptic number.
It is an amenable number.
1351104226141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351104226141 is an equidigital number, since it uses as much as digits as its factorization.
1351104226141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 1351104226141 its reverse (1416224011531), we get a palindrome (2767328237672).
The spelling of 1351104226141 in words is "one trillion, three hundred fifty-one billion, one hundred four million, two hundred twenty-six thousand, one hundred forty-one".
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