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1351104634241 is a prime number
BaseRepresentation
bin10011101010010100000…
…111001001110110000001
311210011102210201212011022
4103222110013021312001
5134114030241243431
62512404445155225
7166420426621205
oct23522407116601
94704383655138
101351104634241
114810003852aa
12199a2a25bb15
139a54097b29b
14495728a2b05
152522a76907b
hex13a941c9d81

1351104634241 has 2 divisors, whose sum is σ = 1351104634242. Its totient is φ = 1351104634240.

The previous prime is 1351104634223. The next prime is 1351104634259. The reversal of 1351104634241 is 1424364011531.

It is a balanced prime because it is at equal distance from previous prime (1351104634223) and next prime (1351104634259).

It can be written as a sum of positive squares in only one way, i.e., 787860388225 + 563244246016 = 887615^2 + 750496^2 .

It is an emirp because it is prime and its reverse (1424364011531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1351104634241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1351104634211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675552317120 + 675552317121.

It is an arithmetic number, because the mean of its divisors is an integer number (675552317121).

Almost surely, 21351104634241 is an apocalyptic number.

It is an amenable number.

1351104634241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351104634241 is an equidigital number, since it uses as much as digits as its factorization.

1351104634241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 35.

Adding to 1351104634241 its reverse (1424364011531), we get a palindrome (2775468645772).

The spelling of 1351104634241 in words is "one trillion, three hundred fifty-one billion, one hundred four million, six hundred thirty-four thousand, two hundred forty-one".