Base | Representation |
---|---|
bin | 10011101010010100111… |
… | …111100000010101101111 |
3 | 11210011110211112100211001 |
4 | 103222110333200111233 |
5 | 134114043032001242 |
6 | 2512410133541131 |
7 | 166420666314646 |
oct | 23522477402557 |
9 | 4704424470731 |
10 | 1351119406447 |
11 | 481008754938 |
12 | 199a331a47a7 |
13 | 9a543a51035 |
14 | 4957482a35d |
15 | 2522bbd5eb7 |
hex | 13a94fe056f |
1351119406447 has 2 divisors, whose sum is σ = 1351119406448. Its totient is φ = 1351119406446.
The previous prime is 1351119406421. The next prime is 1351119406451. The reversal of 1351119406447 is 7446049111531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1351119406447 - 227 = 1350985188719 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1351119406397 and 1351119406406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351219406447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675559703223 + 675559703224.
It is an arithmetic number, because the mean of its divisors is an integer number (675559703224).
Almost surely, 21351119406447 is an apocalyptic number.
1351119406447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351119406447 is an equidigital number, since it uses as much as digits as its factorization.
1351119406447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 46.
The spelling of 1351119406447 in words is "one trillion, three hundred fifty-one billion, one hundred nineteen million, four hundred six thousand, four hundred forty-seven".
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