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1351161540181 is a prime number
BaseRepresentation
bin10011101010010111100…
…000001110111001010101
311210011120202210222102201
4103222113200032321111
5134114134323241211
62512414241004501
7166422020410555
oct23522740167125
94704522728381
101351161540181
1148102a512602
12199a45323731
139a54c6b3b3b
144957a277165
152523075a0c1
hex13a9780ee55

1351161540181 has 2 divisors, whose sum is σ = 1351161540182. Its totient is φ = 1351161540180.

The previous prime is 1351161540173. The next prime is 1351161540191. The reversal of 1351161540181 is 1810451611531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 690137255025 + 661024285156 = 830745^2 + 813034^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351161540181 - 23 = 1351161540173 is a prime.

It is a super-2 number, since 2×13511615401812 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1351161540181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351161540191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675580770090 + 675580770091.

It is an arithmetic number, because the mean of its divisors is an integer number (675580770091).

Almost surely, 21351161540181 is an apocalyptic number.

It is an amenable number.

1351161540181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351161540181 is an equidigital number, since it uses as much as digits as its factorization.

1351161540181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 37.

The spelling of 1351161540181 in words is "one trillion, three hundred fifty-one billion, one hundred sixty-one million, five hundred forty thousand, one hundred eighty-one".