Base | Representation |
---|---|
bin | 11001001010110000… |
… | …01101001000110111 |
3 | 1021212200012221010012 |
4 | 30211120031020313 |
5 | 210133033113101 |
6 | 10112441050435 |
7 | 655561066052 |
oct | 144530151067 |
9 | 37780187105 |
10 | 13512004151 |
11 | 58041a0788 |
12 | 2751186a1b |
13 | 137449a939 |
14 | 922767a99 |
15 | 54138bbbb |
hex | 32560d237 |
13512004151 has 2 divisors, whose sum is σ = 13512004152. Its totient is φ = 13512004150.
The previous prime is 13512004111. The next prime is 13512004159. The reversal of 13512004151 is 15140021531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13512004151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13512004159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756002075 + 6756002076.
It is an arithmetic number, because the mean of its divisors is an integer number (6756002076).
Almost surely, 213512004151 is an apocalyptic number.
13512004151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13512004151 is an equidigital number, since it uses as much as digits as its factorization.
13512004151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 600, while the sum is 23.
Adding to 13512004151 its reverse (15140021531), we get a palindrome (28652025682).
The spelling of 13512004151 in words is "thirteen billion, five hundred twelve million, four thousand, one hundred fifty-one".
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