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13512025403 is a prime number
BaseRepresentation
bin11001001010110000…
…10010010100111011
31021212200021000021022
430211120102110323
5210133034303103
610112441333055
7655561215032
oct144530222473
937780230238
1013512025403
115804205748
12275119718b
1313744a7506
14922771719
15541393138
hex32561253b

13512025403 has 2 divisors, whose sum is σ = 13512025404. Its totient is φ = 13512025402.

The previous prime is 13512025367. The next prime is 13512025409. The reversal of 13512025403 is 30452021531.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (30452021531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13512025403 - 224 = 13495248187 is a prime.

It is not a weakly prime, because it can be changed into another prime (13512025409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756012701 + 6756012702.

It is an arithmetic number, because the mean of its divisors is an integer number (6756012702).

Almost surely, 213512025403 is an apocalyptic number.

13512025403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13512025403 is an equidigital number, since it uses as much as digits as its factorization.

13512025403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 13512025403 its reverse (30452021531), we get a palindrome (43964046934).

The spelling of 13512025403 in words is "thirteen billion, five hundred twelve million, twenty-five thousand, four hundred three".