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13512112673434 = 26756056336717
BaseRepresentation
bin1100010010100000100010…
…1011010001001010011010
31202211202010100211210202121
43010220020223101022122
53232340301321022214
644423213500251454
72563134514452544
oct304501053211232
952752110753677
1013512112673434
11433a500387001
1216228a3240b8a
137702573cab7b
14349dbdbd6694
15186733895424
hexc4a08ad129a

13512112673434 has 4 divisors (see below), whose sum is σ = 20268169010154. Its totient is φ = 6756056336716.

The previous prime is 13512112673431. The next prime is 13512112673441. The reversal of 13512112673434 is 43437621121531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13272928099209 + 239184574225 = 3643203^2 + 489065^2 .

It is not an unprimeable number, because it can be changed into a prime (13512112673431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3378028168357 + ... + 3378028168360.

Almost surely, 213512112673434 is an apocalyptic number.

13512112673434 is a deficient number, since it is larger than the sum of its proper divisors (6756056336720).

13512112673434 is an equidigital number, since it uses as much as digits as its factorization.

13512112673434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6756056336719.

The product of its digits is 362880, while the sum is 43.

Adding to 13512112673434 its reverse (43437621121531), we get a palindrome (56949733794965).

The spelling of 13512112673434 in words is "thirteen trillion, five hundred twelve billion, one hundred twelve million, six hundred seventy-three thousand, four hundred thirty-four".

Divisors: 1 2 6756056336717 13512112673434