13512112673441 has 2 divisors, whose sum is σ = 13512112673442. Its totient is φ = 13512112673440.

The previous prime is 13512112673431. The next prime is 13512112673443. The reversal of 13512112673441 is 14437621121531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12844303371025 + 667809302416 = 3583895^2 + 817196^2 .

It is an emirp because it is prime and its reverse (14437621121531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13512112673441 is a prime.

Together with 13512112673443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13512112673443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756056336720 + 6756056336721.

It is an arithmetic number, because the mean of its divisors is an integer number (6756056336721).

Almost surely, 2^{13512112673441} is an apocalyptic number.

It is an amenable number.

13512112673441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13512112673441 is an equidigital number, since it uses as much as digits as its factorization.

13512112673441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120960, while the sum is 41.

Adding to 13512112673441 its reverse (14437621121531), we get a palindrome (27949733794972).

The spelling of 13512112673441 in words is "thirteen trillion, five hundred twelve billion, one hundred twelve million, six hundred seventy-three thousand, four hundred forty-one".