Base | Representation |
---|---|
bin | 1100010010100000100010… |
… | …1011010001001010010111 |
3 | 1202211202010100211210202111 |
4 | 3010220020223101022113 |
5 | 3232340301321022211 |
6 | 44423213500251451 |
7 | 2563134514452541 |
oct | 304501053211227 |
9 | 52752110753674 |
10 | 13512112673431 |
11 | 433a500386aa9 |
12 | 16228a3240b87 |
13 | 7702573cab78 |
14 | 349dbdbd6691 |
15 | 186733895421 |
hex | c4a08ad1297 |
13512112673431 has 2 divisors, whose sum is σ = 13512112673432. Its totient is φ = 13512112673430.
The previous prime is 13512112673407. The next prime is 13512112673441. The reversal of 13512112673431 is 13437621121531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13512112673431 - 27 = 13512112673303 is a prime.
It is a super-2 number, since 2×135121126734312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13512112673441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756056336715 + 6756056336716.
It is an arithmetic number, because the mean of its divisors is an integer number (6756056336716).
Almost surely, 213512112673431 is an apocalyptic number.
13512112673431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13512112673431 is an equidigital number, since it uses as much as digits as its factorization.
13512112673431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 90720, while the sum is 40.
Adding to 13512112673431 its reverse (13437621121531), we get a palindrome (26949733794962).
The spelling of 13512112673431 in words is "thirteen trillion, five hundred twelve billion, one hundred twelve million, six hundred seventy-three thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •