Base | Representation |
---|---|
bin | 1100010010100110110110… |
… | …0110101011101001111111 |
3 | 1202211220111101002012000222 |
4 | 3010221231212223221333 |
5 | 3232402233312020142 |
6 | 44424053505411555 |
7 | 2563224465315425 |
oct | 304515546535177 |
9 | 52756441065028 |
10 | 13513805970047 |
11 | 434019a190899 |
12 | 1623096339bbb |
13 | 77046716b226 |
14 | 34a100a55115 |
15 | 1867d2372bd2 |
hex | c4a6d9aba7f |
13513805970047 has 8 divisors (see below), whose sum is σ = 13516018365744. Its totient is φ = 13511593758528.
The previous prime is 13513805970043. The next prime is 13513805970079. The reversal of 13513805970047 is 74007950831531.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13513805970047 - 22 = 13513805970043 is a prime.
It is a super-2 number, since 2×135138059700472 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13513805970043) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 233277428 + ... + 233335350.
It is an arithmetic number, because the mean of its divisors is an integer number (1689502295718).
Almost surely, 213513805970047 is an apocalyptic number.
13513805970047 is a deficient number, since it is larger than the sum of its proper divisors (2212395697).
13513805970047 is an equidigital number, since it uses as much as digits as its factorization.
13513805970047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92089.
The product of its (nonzero) digits is 3175200, while the sum is 53.
The spelling of 13513805970047 in words is "thirteen trillion, five hundred thirteen billion, eight hundred five million, nine hundred seventy thousand, forty-seven".
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