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13513805970047 = 94332473357923
BaseRepresentation
bin1100010010100110110110…
…0110101011101001111111
31202211220111101002012000222
43010221231212223221333
53232402233312020142
644424053505411555
72563224465315425
oct304515546535177
952756441065028
1013513805970047
11434019a190899
121623096339bbb
1377046716b226
1434a100a55115
151867d2372bd2
hexc4a6d9aba7f

13513805970047 has 8 divisors (see below), whose sum is σ = 13516018365744. Its totient is φ = 13511593758528.

The previous prime is 13513805970043. The next prime is 13513805970079. The reversal of 13513805970047 is 74007950831531.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13513805970047 - 22 = 13513805970043 is a prime.

It is a super-2 number, since 2×135138059700472 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13513805970043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 233277428 + ... + 233335350.

It is an arithmetic number, because the mean of its divisors is an integer number (1689502295718).

Almost surely, 213513805970047 is an apocalyptic number.

13513805970047 is a deficient number, since it is larger than the sum of its proper divisors (2212395697).

13513805970047 is an equidigital number, since it uses as much as digits as its factorization.

13513805970047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 92089.

The product of its (nonzero) digits is 3175200, while the sum is 53.

The spelling of 13513805970047 in words is "thirteen trillion, five hundred thirteen billion, eight hundred five million, nine hundred seventy thousand, forty-seven".

Divisors: 1 9433 24733 57923 233306389 546387659 1432609559 13513805970047