Base | Representation |
---|---|
bin | 1100010010100111101001… |
… | …1110111011011110000101 |
3 | 1202211221001102122202022112 |
4 | 3010221322132323132011 |
5 | 3232403204120311402 |
6 | 44424131144510405 |
7 | 2563233031020326 |
oct | 304517236733605 |
9 | 52757042582275 |
10 | 13514022041477 |
11 | 43402a0150521 |
12 | 162313677b405 |
13 | 77049cb61749 |
14 | 34a12161c44d |
15 | 1867e6303e52 |
hex | c4a7a7bb785 |
13514022041477 has 2 divisors, whose sum is σ = 13514022041478. Its totient is φ = 13514022041476.
The previous prime is 13514022041431. The next prime is 13514022041551. The reversal of 13514022041477 is 77414022041531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8485301006116 + 5028721035361 = 2912954^2 + 2242481^2 .
It is a cyclic number.
It is not a de Polignac number, because 13514022041477 - 234 = 13496842172293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13514022041407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6757011020738 + 6757011020739.
It is an arithmetic number, because the mean of its divisors is an integer number (6757011020739).
Almost surely, 213514022041477 is an apocalyptic number.
It is an amenable number.
13514022041477 is a deficient number, since it is larger than the sum of its proper divisors (1).
13514022041477 is an equidigital number, since it uses as much as digits as its factorization.
13514022041477 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 188160, while the sum is 41.
The spelling of 13514022041477 in words is "thirteen trillion, five hundred fourteen billion, twenty-two million, forty-one thousand, four hundred seventy-seven".
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