135143124041 has 2 divisors, whose sum is σ = 135143124042. Its totient is φ = 135143124040.

The previous prime is 135143124001. The next prime is 135143124043. The reversal of 135143124041 is 140421341531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101432695225 + 33710428816 = 318485^2 + 183604^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-135143124041 is a prime.

It is a super-2 number, since 2×135143124041² (a number of 23 digits) contains 22 as substring.

Together with 135143124043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 135143123995 and 135143124013.

It is not a weakly prime, because it can be changed into another prime (135143124043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67571562020 + 67571562021.

It is an arithmetic number, because the mean of its divisors is an integer number (67571562021).

Almost surely, 2^135143124041 is an apocalyptic number.

It is an amenable number.

135143124041 is a deficient number, since it is larger than the sum of its proper divisors (1).

135143124041 is an equidigital number, since it uses as much as digits as its factorization.

135143124041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 135143124041 its reverse (140421341531), we get a palindrome (275564465572).

The spelling of 135143124041 in words is "one hundred thirty-five billion, one hundred forty-three million, one hundred twenty-four thousand, forty-one".