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13514341151 is a prime number
BaseRepresentation
bin11001001011000010…
…00111101100011111
31021212211121122212202
430211201013230133
5210134132404101
610113003122115
7655620001343
oct144541075437
937784548782
1013514341151
115805547593
122751b1333b
131374b0858c
14922bb5623
1554169e36b
hex325847b1f

13514341151 has 2 divisors, whose sum is σ = 13514341152. Its totient is φ = 13514341150.

The previous prime is 13514341133. The next prime is 13514341171. The reversal of 13514341151 is 15114341531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13514341151 - 226 = 13447232287 is a prime.

It is a super-2 number, since 2×135143411512 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13514341171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6757170575 + 6757170576.

It is an arithmetic number, because the mean of its divisors is an integer number (6757170576).

Almost surely, 213514341151 is an apocalyptic number.

13514341151 is a deficient number, since it is larger than the sum of its proper divisors (1).

13514341151 is an equidigital number, since it uses as much as digits as its factorization.

13514341151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3600, while the sum is 29.

Adding to 13514341151 its reverse (15114341531), we get a palindrome (28628682682).

The spelling of 13514341151 in words is "thirteen billion, five hundred fourteen million, three hundred forty-one thousand, one hundred fifty-one".