Base | Representation |
---|---|
bin | 111110111011110110… |
… | …0011000111011100101 |
3 | 110220211222112121201002 |
4 | 1331313230120323211 |
5 | 4203242420030313 |
6 | 142031002443045 |
7 | 12523123664051 |
oct | 1756754307345 |
9 | 426758477632 |
10 | 135152111333 |
11 | 52354930688 |
12 | 2223a203485 |
13 | c98b3c1315 |
14 | 6781844c61 |
15 | 37b0315058 |
hex | 1f77b18ee5 |
135152111333 has 2 divisors, whose sum is σ = 135152111334. Its totient is φ = 135152111332.
The previous prime is 135152111329. The next prime is 135152111387. The reversal of 135152111333 is 333111251531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 131767548004 + 3384563329 = 362998^2 + 58177^2 .
It is a cyclic number.
It is not a de Polignac number, because 135152111333 - 22 = 135152111329 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135152111296 and 135152111305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135152111033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67576055666 + 67576055667.
It is an arithmetic number, because the mean of its divisors is an integer number (67576055667).
Almost surely, 2135152111333 is an apocalyptic number.
It is an amenable number.
135152111333 is a deficient number, since it is larger than the sum of its proper divisors (1).
135152111333 is an equidigital number, since it uses as much as digits as its factorization.
135152111333 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4050, while the sum is 29.
Adding to 135152111333 its reverse (333111251531), we get a palindrome (468263362864).
The spelling of 135152111333 in words is "one hundred thirty-five billion, one hundred fifty-two million, one hundred eleven thousand, three hundred thirty-three".
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