Base | Representation |
---|---|
bin | 10011101010110111101… |
… | …011110010011000110011 |
3 | 11210012222101201201211012 |
4 | 103222313223302120303 |
5 | 134121241032040201 |
6 | 2512544004541135 |
7 | 166441264444634 |
oct | 23526753623063 |
9 | 4705871651735 |
10 | 1351701440051 |
11 | 481287251346 |
12 | 199b760b17ab |
13 | 9a6074c9011 |
14 | 495cbc5788b |
15 | 25262d555bb |
hex | 13ab7af2633 |
1351701440051 has 2 divisors, whose sum is σ = 1351701440052. Its totient is φ = 1351701440050.
The previous prime is 1351701440003. The next prime is 1351701440057. The reversal of 1351701440051 is 1500441071531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1351701440051 is a prime.
It is not a weakly prime, because it can be changed into another prime (1351701440057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675850720025 + 675850720026.
It is an arithmetic number, because the mean of its divisors is an integer number (675850720026).
Almost surely, 21351701440051 is an apocalyptic number.
1351701440051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351701440051 is an equidigital number, since it uses as much as digits as its factorization.
1351701440051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 32.
The spelling of 1351701440051 in words is "one trillion, three hundred fifty-one billion, seven hundred one million, four hundred forty thousand, fifty-one".
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