Base | Representation |
---|---|
bin | 10011101010110111111… |
… | …010111111100011000101 |
3 | 11210012222200020020200021 |
4 | 103222313322333203011 |
5 | 134121243042113432 |
6 | 2512544230215141 |
7 | 166441343356054 |
oct | 23526772774305 |
9 | 4705880206607 |
10 | 1351705426117 |
11 | 481289524112 |
12 | 199b774b44b1 |
13 | 9a608293437 |
14 | 495cc5b439b |
15 | 25263391697 |
hex | 13ab7ebf8c5 |
1351705426117 has 2 divisors, whose sum is σ = 1351705426118. Its totient is φ = 1351705426116.
The previous prime is 1351705426091. The next prime is 1351705426129. The reversal of 1351705426117 is 7116245071531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 937955447361 + 413749978756 = 968481^2 + 643234^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1351705426117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351705426187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675852713058 + 675852713059.
It is an arithmetic number, because the mean of its divisors is an integer number (675852713059).
Almost surely, 21351705426117 is an apocalyptic number.
It is an amenable number.
1351705426117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351705426117 is an equidigital number, since it uses as much as digits as its factorization.
1351705426117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 176400, while the sum is 43.
The spelling of 1351705426117 in words is "one trillion, three hundred fifty-one billion, seven hundred five million, four hundred twenty-six thousand, one hundred seventeen".
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