Base | Representation |
---|---|
bin | 10011101010110111111… |
… | …011000100010100001111 |
3 | 11210012222200021020110121 |
4 | 103222313323010110033 |
5 | 134121243043230042 |
6 | 2512544230445411 |
7 | 166441343500024 |
oct | 23526773042417 |
9 | 4705880236417 |
10 | 1351705445647 |
11 | 481289537857 |
12 | 199b77503867 |
13 | 9a60829c2ab |
14 | 495cc5bb54b |
15 | 25263397367 |
hex | 13ab7ec450f |
1351705445647 has 2 divisors, whose sum is σ = 1351705445648. Its totient is φ = 1351705445646.
The previous prime is 1351705445627. The next prime is 1351705445677. The reversal of 1351705445647 is 7465445071531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1351705445647 is a prime.
It is a super-2 number, since 2×13517054456472 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1351705445594 and 1351705445603.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1351705445617) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675852722823 + 675852722824.
It is an arithmetic number, because the mean of its divisors is an integer number (675852722824).
Almost surely, 21351705445647 is an apocalyptic number.
1351705445647 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351705445647 is an equidigital number, since it uses as much as digits as its factorization.
1351705445647 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7056000, while the sum is 52.
The spelling of 1351705445647 in words is "one trillion, three hundred fifty-one billion, seven hundred five million, four hundred forty-five thousand, six hundred forty-seven".
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