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1351757705653 is a prime number
BaseRepresentation
bin10011101010111011000…
…010011011000110110101
311210020010022121022201101
4103222323002123012311
5134121344433040103
62512553334530101
7166442546626405
oct23527302330665
94706108538641
101351757705653
11481305a91543
12199b90b06931
139a616069284
14495d5502805
1525267c6ba1d
hex13abb09b1b5

1351757705653 has 2 divisors, whose sum is σ = 1351757705654. Its totient is φ = 1351757705652.

The previous prime is 1351757705593. The next prime is 1351757705671. The reversal of 1351757705653 is 3565077571531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 920999137969 + 430758567684 = 959687^2 + 656322^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1351757705653 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1351757705594 and 1351757705603.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351757705693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675878852826 + 675878852827.

It is an arithmetic number, because the mean of its divisors is an integer number (675878852827).

Almost surely, 21351757705653 is an apocalyptic number.

It is an amenable number.

1351757705653 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351757705653 is an equidigital number, since it uses as much as digits as its factorization.

1351757705653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11576250, while the sum is 55.

The spelling of 1351757705653 in words is "one trillion, three hundred fifty-one billion, seven hundred fifty-seven million, seven hundred five thousand, six hundred fifty-three".