Base | Representation |
---|---|
bin | 11110101111100110010010… |
… | …100000111000110110110000 |
3 | 122201202011122022022211000122 |
4 | 132233212102200320312300 |
5 | 120210304314311243100 |
6 | 1155323403420505412 |
7 | 40323524265610061 |
oct | 3657462240706660 |
9 | 581664568284018 |
10 | 135212323540400 |
11 | 3a0a025172a217 |
12 | 131b90796ab268 |
13 | 5a5a60cb50952 |
14 | 25564505c4568 |
15 | 10972b20bd985 |
hex | 7af992838db0 |
135212323540400 has 60 divisors (see below), whose sum is σ = 329696079121992. Its totient is φ = 53277691653120.
The previous prime is 135212323540391. The next prime is 135212323540451. The reversal of 135212323540400 is 4045323212531.
It is a super-3 number, since 3×1352123235404003 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2522591177 + ... + 2522644776.
Almost surely, 2135212323540400 is an apocalyptic number.
135212323540400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
135212323540400 is an abundant number, since it is smaller than the sum of its proper divisors (194483755581592).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135212323540400 is a wasteful number, since it uses less digits than its factorization.
135212323540400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5045236038 (or 5045236027 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 135212323540400 its reverse (4045323212531), we get a palindrome (139257646752931).
The spelling of 135212323540400 in words is "one hundred thirty-five trillion, two hundred twelve billion, three hundred twenty-three million, five hundred forty thousand, four hundred".
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