Base | Representation |
---|---|
bin | 1100010011000011001110… |
… | …0101000110101011110011 |
3 | 1202212122011011202112221100 |
4 | 3010300303211012223303 |
5 | 3233013333114200111 |
6 | 44431353344255443 |
7 | 2563614311105205 |
oct | 304606345065363 |
9 | 52778134675840 |
10 | 13521422412531 |
11 | 43434484a3860 |
12 | 1624661011583 |
13 | 7710ac0a8b27 |
14 | 34a6243d8775 |
15 | 186acad56756 |
hex | c4c33946af3 |
13521422412531 has 48 divisors (see below), whose sum is σ = 21521453541120. Its totient is φ = 8112151080000.
The previous prime is 13521422412521. The next prime is 13521422412551.
13521422412531 is a `hidden beast` number, since 1 + 3 + 5 + 214 + 22 + 412 + 5 + 3 + 1 = 666.
13521422412531 is nontrivially palindromic in base 10.
13521422412531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13521422412531 - 25 = 13521422412499 is a prime.
It is a super-2 number, since 2×135214224125312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13521422412521) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 54661116 + ... + 54907926.
It is an arithmetic number, because the mean of its divisors is an integer number (448363615440).
Almost surely, 213521422412531 is an apocalyptic number.
13521422412531 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13521422412531 is a deficient number, since it is larger than the sum of its proper divisors (8000031128589).
13521422412531 is a wasteful number, since it uses less digits than its factorization.
13521422412531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252408 (or 252405 counting only the distinct ones).
The product of its digits is 57600, while the sum is 36.
It can be divided in two parts, 1352142 and 2412531, that added together give a palindrome (3764673).
The spelling of 13521422412531 in words is "thirteen trillion, five hundred twenty-one billion, four hundred twenty-two million, four hundred twelve thousand, five hundred thirty-one".
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