Base | Representation |
---|---|
bin | 1100010011000011001110… |
… | …0101000110101100000111 |
3 | 1202212122011011202112222002 |
4 | 3010300303211012230013 |
5 | 3233013333114200201 |
6 | 44431353344255515 |
7 | 2563614311105234 |
oct | 304606345065407 |
9 | 52778134675862 |
10 | 13521422412551 |
11 | 43434484a3879 |
12 | 162466101159b |
13 | 7710ac0a8b41 |
14 | 34a6243d878b |
15 | 186acad5676b |
hex | c4c33946b07 |
13521422412551 has 2 divisors, whose sum is σ = 13521422412552. Its totient is φ = 13521422412550.
The previous prime is 13521422412521. The next prime is 13521422412557. The reversal of 13521422412551 is 15521422412531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13521422412551 - 222 = 13521418218247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13521422412557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760711206275 + 6760711206276.
It is an arithmetic number, because the mean of its divisors is an integer number (6760711206276).
Almost surely, 213521422412551 is an apocalyptic number.
13521422412551 is a deficient number, since it is larger than the sum of its proper divisors (1).
13521422412551 is an equidigital number, since it uses as much as digits as its factorization.
13521422412551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 96000, while the sum is 38.
The spelling of 13521422412551 in words is "thirteen trillion, five hundred twenty-one billion, four hundred twenty-two million, four hundred twelve thousand, five hundred fifty-one".
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