Base | Representation |
---|---|
bin | 10011101011010010000… |
… | …000101101001111011101 |
3 | 11210021010011211222201221 |
4 | 103223102000231033131 |
5 | 134123142120202423 |
6 | 2513055503533341 |
7 | 166455236661301 |
oct | 23532200551735 |
9 | 4707104758657 |
10 | 1352143131613 |
11 | 48149360279a |
12 | 19a079bba251 |
13 | 9a677b77081 |
14 | 49630791d01 |
15 | 2528ba01e5d |
hex | 13ad202d3dd |
1352143131613 has 4 divisors (see below), whose sum is σ = 1352146072320. Its totient is φ = 1352140190908.
The previous prime is 1352143131541. The next prime is 1352143131637. The reversal of 1352143131613 is 3161313412531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1352143131613 is a prime.
It is a super-3 number, since 3×13521431316133 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1352143135613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 614653 + ... + 1755586.
It is an arithmetic number, because the mean of its divisors is an integer number (338036518080).
Almost surely, 21352143131613 is an apocalyptic number.
It is an amenable number.
1352143131613 is a deficient number, since it is larger than the sum of its proper divisors (2940707).
1352143131613 is an equidigital number, since it uses as much as digits as its factorization.
1352143131613 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2940706.
The product of its digits is 19440, while the sum is 34.
The spelling of 1352143131613 in words is "one trillion, three hundred fifty-two billion, one hundred forty-three million, one hundred thirty-one thousand, six hundred thirteen".
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