1352143131541 has 2 divisors, whose sum is σ = 1352143131542. Its totient is φ = 1352143131540.

The previous prime is 1352143131511. The next prime is 1352143131637. The reversal of 1352143131541 is 1451313412531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1155764754225 + 196378377316 = 1075065^2 + 443146^2 .

It is a cyclic number.

It is not a de Polignac number, because 1352143131541 - 2¹⁵ = 1352143098773 is a prime.

It is a super-3 number, since 3×1352143131541³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1352143131497 and 1352143131506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1352143131511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676071565770 + 676071565771.

It is an arithmetic number, because the mean of its divisors is an integer number (676071565771).

Almost surely, 2^{1352143131541} is an apocalyptic number.

It is an amenable number.

1352143131541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1352143131541 is an equidigital number, since it uses as much as digits as its factorization.

1352143131541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 21600, while the sum is 34.

The spelling of 1352143131541 in words is "one trillion, three hundred fifty-two billion, one hundred forty-three million, one hundred thirty-one thousand, five hundred forty-one".