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1352302740253 is a prime number
BaseRepresentation
bin10011101011011011100…
…001100100001100011101
311210021112022011221122001
4103223123201210030131
5134124004000142003
62513123404522301
7166462215430513
oct23533341441435
94707468157561
101352302740253
11481565708063
1219a103550391
139a6a1c5b65a
1449647a5c4b3
152529aa2d61d
hex13adb86431d

1352302740253 has 2 divisors, whose sum is σ = 1352302740254. Its totient is φ = 1352302740252.

The previous prime is 1352302740181. The next prime is 1352302740277. The reversal of 1352302740253 is 3520472032531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1245516264729 + 106786475524 = 1116027^2 + 326782^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1352302740253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1352302740653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676151370126 + 676151370127.

It is an arithmetic number, because the mean of its divisors is an integer number (676151370127).

Almost surely, 21352302740253 is an apocalyptic number.

It is an amenable number.

1352302740253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1352302740253 is an equidigital number, since it uses as much as digits as its factorization.

1352302740253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 37.

Adding to 1352302740253 its reverse (3520472032531), we get a palindrome (4872774772784).

The spelling of 1352302740253 in words is "one trillion, three hundred fifty-two billion, three hundred two million, seven hundred forty thousand, two hundred fifty-three".