Base | Representation |
---|---|
bin | 11001001100010001… |
… | …10100101010011101 |
3 | 1021220120012102201001 |
4 | 30212020310222131 |
5 | 210144313431312 |
6 | 10114014150301 |
7 | 656104316656 |
oct | 144610645235 |
9 | 37816172631 |
10 | 13524748957 |
11 | 5810406085 |
12 | 27554b2391 |
13 | 1377010945 |
14 | 92432452d |
15 | 542558057 |
hex | 326234a9d |
13524748957 has 2 divisors, whose sum is σ = 13524748958. Its totient is φ = 13524748956.
The previous prime is 13524748933. The next prime is 13524748969. The reversal of 13524748957 is 75984742531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8521874596 + 5002874361 = 92314^2 + 70731^2 .
It is a cyclic number.
It is not a de Polignac number, because 13524748957 - 211 = 13524746909 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13524748898 and 13524748907.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13524748907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762374478 + 6762374479.
It is an arithmetic number, because the mean of its divisors is an integer number (6762374479).
Almost surely, 213524748957 is an apocalyptic number.
It is an amenable number.
13524748957 is a deficient number, since it is larger than the sum of its proper divisors (1).
13524748957 is an equidigital number, since it uses as much as digits as its factorization.
13524748957 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8467200, while the sum is 55.
The spelling of 13524748957 in words is "thirteen billion, five hundred twenty-four million, seven hundred forty-eight thousand, nine hundred fifty-seven".
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