Base | Representation |
---|---|
bin | 11001001100010110… |
… | …11101011011110001 |
3 | 1021220121111112222011 |
4 | 30212023131123301 |
5 | 210200003041431 |
6 | 10114041042521 |
7 | 656113226245 |
oct | 144613353361 |
9 | 37817445864 |
10 | 13525440241 |
11 | 5810838495 |
12 | 2755786441 |
13 | 13771c34a1 |
14 | 924464425 |
15 | 542642cb1 |
hex | 3262dd6f1 |
13525440241 has 2 divisors, whose sum is σ = 13525440242. Its totient is φ = 13525440240.
The previous prime is 13525440223. The next prime is 13525440259. The reversal of 13525440241 is 14204452531.
It is a balanced prime because it is at equal distance from previous prime (13525440223) and next prime (13525440259).
It can be written as a sum of positive squares in only one way, i.e., 13524759616 + 680625 = 116296^2 + 825^2 .
It is a cyclic number.
It is not a de Polignac number, because 13525440241 - 27 = 13525440113 is a prime.
It is not a weakly prime, because it can be changed into another prime (13525440211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762720120 + 6762720121.
It is an arithmetic number, because the mean of its divisors is an integer number (6762720121).
Almost surely, 213525440241 is an apocalyptic number.
It is an amenable number.
13525440241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13525440241 is an equidigital number, since it uses as much as digits as its factorization.
13525440241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 13525440241 its reverse (14204452531), we get a palindrome (27729892772).
The spelling of 13525440241 in words is "thirteen billion, five hundred twenty-five million, four hundred forty thousand, two hundred forty-one".
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