Base | Representation |
---|---|
bin | 1100010011010110100111… |
… | …1110111110101011100010 |
3 | 1202220010121010000010122212 |
4 | 3010311221332332223202 |
5 | 3233110014303214300 |
6 | 44434014220002122 |
7 | 2564160335022131 |
oct | 304655176765342 |
9 | 52803533003585 |
10 | 13526630132450 |
11 | 4345680086916 |
12 | 1625675090342 |
13 | 77172bc957c6 |
14 | 34a999ccb918 |
15 | 186cd313e935 |
hex | c4d69fbeae2 |
13526630132450 has 48 divisors (see below), whose sum is σ = 25188589077120. Its totient is φ = 5404405128000.
The previous prime is 13526630132413. The next prime is 13526630132467. The reversal of 13526630132450 is 5423103662531.
It is a junction number, because it is equal to n+sod(n) for n = 13526630132398 and 13526630132407.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 339922055 + ... + 339961845.
It is an arithmetic number, because the mean of its divisors is an integer number (524762272440).
Almost surely, 213526630132450 is an apocalyptic number.
13526630132450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13526630132450 is a deficient number, since it is larger than the sum of its proper divisors (11661958944670).
13526630132450 is a wasteful number, since it uses less digits than its factorization.
13526630132450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47483 (or 47478 counting only the distinct ones).
The product of its (nonzero) digits is 388800, while the sum is 41.
Adding to 13526630132450 its reverse (5423103662531), we get a palindrome (18949733794981).
The spelling of 13526630132450 in words is "thirteen trillion, five hundred twenty-six billion, six hundred thirty million, one hundred thirty-two thousand, four hundred fifty".
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