13527401 has 2 divisors, whose sum is σ = 13527402. Its totient is φ = 13527400.

The previous prime is 13527383. The next prime is 13527419. The reversal of 13527401 is 10472531.

It is a balanced prime because it is at equal distance from previous prime (13527383) and next prime (13527419).

It can be written as a sum of positive squares in only one way, i.e., 10569001 + 2958400 = 3251^2 + 1720^2 .

It is an emirp because it is prime and its reverse (10472531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13527401 - 2⁶ = 13527337 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13527431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6763700 + 6763701.

It is an arithmetic number, because the mean of its divisors is an integer number (6763701).

Almost surely, 2^13527401 is an apocalyptic number.

It is an amenable number.

13527401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13527401 is an equidigital number, since it uses as much as digits as its factorization.

13527401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 13527401 is about 3677.9615278031. The cubic root of 13527401 is about 238.2711466142.

Adding to 13527401 its reverse (10472531), we get a palindrome (23999932).

The spelling of 13527401 in words is "thirteen million, five hundred twenty-seven thousand, four hundred one".