Base | Representation |
---|---|
bin | 1100010011011101001000… |
… | …0101001111111111011011 |
3 | 1202220022002211022012220201 |
4 | 3010313102011033333123 |
5 | 3233122103402403213 |
6 | 44434503405003031 |
7 | 2564251532555551 |
oct | 304672205177733 |
9 | 52808084265821 |
10 | 13528376606683 |
11 | 4346396a01854 |
12 | 1625a81b53477 |
13 | 771949a64703 |
14 | 34aac3c2dbd1 |
15 | 186d866236dd |
hex | c4dd214ffdb |
13528376606683 has 2 divisors, whose sum is σ = 13528376606684. Its totient is φ = 13528376606682.
The previous prime is 13528376606669. The next prime is 13528376606741. The reversal of 13528376606683 is 38660667382531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13528376606683 - 213 = 13528376598491 is a prime.
It is a super-3 number, since 3×135283766066833 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13528376606783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6764188303341 + 6764188303342.
It is an arithmetic number, because the mean of its divisors is an integer number (6764188303342).
Almost surely, 213528376606683 is an apocalyptic number.
13528376606683 is a deficient number, since it is larger than the sum of its proper divisors (1).
13528376606683 is an equidigital number, since it uses as much as digits as its factorization.
13528376606683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 156764160, while the sum is 64.
The spelling of 13528376606683 in words is "thirteen trillion, five hundred twenty-eight billion, three hundred seventy-six million, six hundred six thousand, six hundred eighty-three".
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