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135302540435521 is a prime number
BaseRepresentation
bin11110110000111010010011…
…110111000010000001000001
3122202001210111200022221022121
4132300322103313002001001
5120213244100322414041
61155433043510004241
740333200040555654
oct3660722367020101
9582053450287277
10135302540435521
113a125537822878
1213212657046681
135a65c89894324
14255a96c22189b
1510997e24e07d1
hex7b0e93dc2041

135302540435521 has 2 divisors, whose sum is σ = 135302540435522. Its totient is φ = 135302540435520.

The previous prime is 135302540435519. The next prime is 135302540435561. The reversal of 135302540435521 is 125534045203531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77144163080625 + 58158377354896 = 8783175^2 + 7626164^2 .

It is a cyclic number.

It is not a de Polignac number, because 135302540435521 - 21 = 135302540435519 is a prime.

Together with 135302540435519, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (135302540435561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67651270217760 + 67651270217761.

It is an arithmetic number, because the mean of its divisors is an integer number (67651270217761).

Almost surely, 2135302540435521 is an apocalyptic number.

It is an amenable number.

135302540435521 is a deficient number, since it is larger than the sum of its proper divisors (1).

135302540435521 is an equidigital number, since it uses as much as digits as its factorization.

135302540435521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080000, while the sum is 43.

The spelling of 135302540435521 in words is "one hundred thirty-five trillion, three hundred two billion, five hundred forty million, four hundred thirty-five thousand, five hundred twenty-one".