Base | Representation |
---|---|
bin | 11001001101000001… |
… | …10100110101001111 |
3 | 1021221000001002220111 |
4 | 30212200310311033 |
5 | 210202421303403 |
6 | 10114401100451 |
7 | 656211644266 |
oct | 144640646517 |
9 | 37830032814 |
10 | 13531041103 |
11 | 5813a134a8 |
12 | 2757627727 |
13 | 13784048c8 |
14 | 9250c15dd |
15 | 542d9c56d |
hex | 326834d4f |
13531041103 has 2 divisors, whose sum is σ = 13531041104. Its totient is φ = 13531041102.
The previous prime is 13531041091. The next prime is 13531041109. The reversal of 13531041103 is 30114013531.
13531041103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13531041103 - 29 = 13531040591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13531041109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765520551 + 6765520552.
It is an arithmetic number, because the mean of its divisors is an integer number (6765520552).
Almost surely, 213531041103 is an apocalyptic number.
13531041103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531041103 is an equidigital number, since it uses as much as digits as its factorization.
13531041103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 13531041103 its reverse (30114013531), we get a palindrome (43645054634).
The spelling of 13531041103 in words is "thirteen billion, five hundred thirty-one million, forty-one thousand, one hundred three".
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